Given y = 4/√(2x-3), x > 1.5

(a)Find dy/dx

(b)Explain why the graph of y = 4/√(2x – 3) does not have a stationary point

(c)State whether y = 4√(2x – 3) is an increasing or decreasing function. Explain your answer clearly.

y = 4(2x – 3)^{-1/2}

dy/dx = -2(2x – 3)^{-3/2}(2)

= -4(2x – 3)^{-3/2}

(b) Since, dy/dx = -4(2x – 3)^{-3/2} , (2x-3) is always positive

(2x – 3 )^{-3/2} > 0

- dy/dx < 0, dy/dx ≠ 0, therefore graph has no stationary point