2019 RI P2 Q2
2019 RI P2 Q2 (a) The curve $y=text{f}left( x right)$ passes through the point $left( 0,81 right)$ and has gradient given by $frac{text{d}y}{text{d}x}={{left( frac{1}{3}y-15x right)}^{frac{1}{3}}}$. Find the first three non-zero
2019 RI P2 Q2 (a) The curve $y=text{f}left( x right)$ passes through the point $left( 0,81 right)$ and has gradient given by $frac{text{d}y}{text{d}x}={{left( frac{1}{3}y-15x right)}^{frac{1}{3}}}$. Find the first three non-zero
2022 SAJC Promo Q10 Starting from the coordinates $left( 0,8 right)$, a particle $P$ moves in the positive $x$-direction and then in the negative $y$-direction alternatively (see Fig. 1). Hence,
2021 TJC P2 Q2 It is given that $text{f}left( r right)=frac{1}{r!}$ where $r$ is a positive integer. (i) Show that $text{f}left( r right)-text{f}left( r+1 right)=frac{r}{left( r+1 right)!}$. [1] (ii) The
2021 SAJC Revision Package Q2 The sum of the first $n$ terms of a series, ${{S}_{n}}$, is given by $frac{{{a}^{n}}}{{{2}^{n-1}}}-2$, where $a$ is a non-zero constant and $ane 2$. (i)
These Ten-Year-Series (TYS) worked solutions with video explanations for 1983 A Level H2 Mathematics Paper 1 Question 7 are suggested by Mr Gan. For any comments or suggestions please contact
It’s no secret that college students struggle with time management. Some of us find it challenging to strike a healthy balance between schoolwork and other responsibilities, or even just have
AM Coordinate Geometry Practice Question 1 The figure shows a right-angled triangle $ABC$, where points $A$, $B$ and $C$ are $Aleft( -2,8 right)$, $left( k,0 right)$ and $left( 10,4 right)$
December is a great time to travel since winter holidays are happening across the world. This can be a great time to get out there and see the world. When
3 AM Quadratic Functions Practice Q2 In a game called Aim-High, a player places his token at a fixed point, then chooses one of three given options to release the
Maclaurin Series – Small Angle Approximation Q1 In the triangle $ABC$, angle $BAC=frac{pi }{3}$ radians, angle $ABC=left( frac{pi }{3}+x right)$ radians and angle $ACB=left( frac{pi }{3}-x right)$ radians, where $x$