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###### Ten-Year-Series (TYS) Solutions | Past Year Exam Questions

# 2007 A Level H2 Math

These Ten-Year-Series (TYS) worked solutions with video explanations for 2007 A Level H2 Mathematics are suggested by Mr Gan. For any comments or suggestions please contact us at support@timganmath.edu.sg.

**2007 Paper 1 Question 4 (AM 9233)**

**Suggested Handwritten and Video Solutions**

**2007 A Level H2 Math Paper 1 Question 4**

**Suggested Handwritten and Video Solutions**

**2007 A Level H2 Math Paper 1 Question 8**

**Suggested Handwritten and Video Solutions**

**2007 A Level H2 Math Paper 1 Question 11**

A curve has parametric equations $x={{\cos }^{2}}t$, $y={{\sin }^{3}}t$, for $0\le t\le \frac{\pi }{2}$.

**Suggested Handwritten and Video Solutions**

**2007 A Level H2 Math Paper 2 Question 8 [Modified]**

**Suggested Handwritten and Video Solutions**

Paper 1

Paper 2

- Q4 (AM 9233)
- Q4
- Q8
- Q11

- (i)
- (ii)

- (i)
- (ii)

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- (i)
- (ii)
- (iii)

- (i)
- (ii)
- (iii)

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(i)

Sketch the curve.

[2]

(i) Sketch the curve.

[2]

(ii)

The tangent to the curve at the point $\left( {{\cos }^{2}}\theta ,\,\,{{\sin }^{3}}\theta \right)$ where $0<\theta <\frac{\pi }{2}$, meets the $x$- and $y$-axes at $Q$ and $R$ respectively. The origin is denoted by $O$. Show that the area of triangle $OQR$ is $\frac{1}{12}\sin \theta {{\left( 3{{\cos }^{2}}\theta +2{{\sin }^{2}}\theta \right)}^{2}}$.

[6]

(ii) The tangent to the curve at the point $\left( {{\cos }^{2}}\theta ,\,\,{{\sin }^{3}}\theta \right)$ where $0<\theta <\frac{\pi }{2}$, meets the $x$- and $y$-axes at $Q$ and $R$ respectively. The origin is denoted by $O$. Show that the area of triangle $OQR$ is $\frac{1}{12}\sin \theta {{\left( 3{{\cos }^{2}}\theta +2{{\sin }^{2}}\theta \right)}^{2}}$.

[6]

(iii)

Show that the area under the curve for $0\le t\le \frac{\pi }{2}$ is $2\int_{0}^{\frac{\pi }{2}}{\cos t{{\sin }^{4}}\text{t}\,\,\text{d}t}$, and use the substituition $\sin t=u$ to find this area.

[5]

(iii)

Show that the area under the curve for $0\le t\le \frac{\pi }{2}$ is $2\int_{0}^{\frac{\pi }{2}}{\cos t{{\sin }^{4}}\text{t}\,\,\text{d}t}$, and use the substituition $\sin t=u$ to find this area.

[5]

- (i)
- (ii)
- (iii)

- (i)
- (ii)
- (iii)

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- Q8

- (i)
- (ii)
- (iii)
- (iv)
- (v)

- (i)
- (ii)
- (iii)
- (iv)
- (v)

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