y = Ax2 – b/x Solution y = mx + c Method 1: xy = Ax3 – b y=xy, m = a, x=x3 , c = -b Method 2: y/x2 = a – b/x3 y/x2 = -b(1/x2) + a Y = y/x2, m = -b, X = 1/x3, C=a

In the figure, AB is parallel to PRQ, T and P are the midpoints of CQ and CA respectively and ART is a straight line. Prove that TR : RA = 1 : 2. Solution Point Q is the midpoint of BC (midpoint theorem) QB : QC QC […]