2022 HCI J1 BT Q7

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Timothy Gan

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2022 HCI J1 BT Q7

It is given that ${{u}_{r}}=\frac{1}{\left( r+2k \right)!}$, where $r\in {{\mathbb{Z}}^{+}}$ and $k$ is a positive constant.

(i)

Show that ${{u}_{r}}-{{u}_{r+1}}=\frac{r+2k}{\left( r+2k+1 \right)!}$.

[1]

(ii)

Hence use the method of differences to find $\sum\limits_{r=1}^{n}{\frac{r+2k}{\left( r+2k+1 \right)!}}$ in terms of $n$ and $k$. You need not simplify your answer.

[3]

Let ${{S}_{n}}$ denote the sum of the first $n$ terms of the series

$\frac{1}{4\,\,\,2!}+\frac{1}{5\,\,\,3!}+\frac{1}{6\,\,\,4!}+…$.

(iii)

By finding a suitable integer value of k and using the result obtained in part (ii), find ${{S}_{n}}$ in terms of $n$ .

[2]

(iv)

Deduce that ${{S}_{n}}<\frac{1}{6}$ for all $n\in {{\mathbb{Z}}^{+}}$.

[1]

(v)

Find the least value of $n$ for which ${{S}_{n}}$ is within ${{10}^{-20}}$ of the sum to infinity.

[2]

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Published: 21st March 2024
2022 HCI J1 BT Q7
Written by
Timothy Gan
This is Tim. Tim loves to teach math. Tim seeks to improve his teaching incessantly! Help Tim by telling him how he can do better.
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Published: 21st March 2024

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