2022 HCI Promo Q2
The equation of a curve $G$ is given by
${{x}^{2}}y-\ln y=1$, where $x<0$ and $y>0$.
(a)
Show that $\frac{\text{d}y}{\text{d}x}=\frac{2x{{y}^{2}}}{1-{{x}^{2}}y}$.
[3]
(b)
Find the equation of the tangent to $G$ at the point $P$ where $y=1$.
[3]
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